Another challenge in the shellCTF Cryptography category was called encoder and this is how it was solved. Using Cybershef I chose the Encryption / Encoding category and moved the ROT13 block to the Recipe. ROT13 which is a simple Caeser cipher. Using this cipher I chose the rotate amount to 19 to get the flag. (-7 will also work as 26 – 7 is 19). Below is a short video to show the process: